Array Initialization with Random Numbers with out Repetitive Value.

Array Initialization with Random Numbers With Out Repetitive value.

Source code:

import java.util.Random;  

class ArrayInitRandom

{

public static void main(String args[])

{

int arrayVaules[]=new int[10];  

       // choose array size as per your requirement. here 10.

int tempnum;

int t=0; // just for checking purpose

Random r= new Random();

for(int j=0;;)

         {

t=0;

/*Random number generated and stored in tempnum.

   Here 10 is given as max limit (in method 

   r.nextInt(10)) because i want to initialize 

  array with values from 0 to 9. You can specify    according to your requirement. */

tempnum= r.nextInt(10);   

// This for loop is to check whether generated random //number is already there in array or 

//not.If it is already there t variable is set to 1

for(int k=0;k<j;k++)  

{

if(tempnum==arrayVaules[k])

{

t=1;

}

}

if(t!=1)

{

                arrayVaules[j]=tempnum;

j++;

if(j==10)   // My array size is 10. 

        {

break;

}

}

                       }

//To show Out put. 

for(int l=0;l<10;l++)

{

System.out.println("value at index   "+ l +"   is   "+arrayVaules[l]);

}

}

}

• Save the file with name ArrayInitRandom.java 
• Complie with: javac ArrayInitRandom.java
• Run with: java ArrayInitRandom

Out Put is as following :

(Note that Out put may very as we have initialized with random numbers.)